return key_eq(*data, *need);
}
+static void move_to_front(struct key_user res[], unsigned int elem)
+{
+ if (elem != 0) {
+ struct key_user tmp = res[elem];
+ memmove(res + 1, res, elem*sizeof(res[0]));
+ res[0] = tmp;
+ }
+}
+
+static void restore_to_pos(struct key_user res[], unsigned int elem)
+{
+ if (elem != 0) {
+ struct key_user tmp = res[0];
+ memmove(res, res + 1, elem*sizeof(res[0]));
+ res[elem] = tmp;
+ }
+}
+
static bool sort_deps(char *filename[], struct op *op[],
struct key_user res[], unsigned num,
- const TDB_DATA *data)
+ const TDB_DATA *data, unsigned num_files)
{
- unsigned int i;
+ unsigned int i, files_done;
+ struct op *this_op;
+ bool done[num_files];
/* Nothing left? We're sorted. */
if (num == 0)
return true;
- for (i = 0; i < num; i++) {
- struct op *this_op = &op[res[i].file][res[i].op_num];
+ memset(done, 0, sizeof(done));
+
+ /* Since ops within a trace file are ordered, we just need to figure
+ * out which file to try next. Since we don't take into account
+ * inter-key relationships (which exist by virtue of trace file order),
+ * we minimize the chance of harm by trying to keep in serial order. */
+ for (files_done = 0, i = 0; i < num && files_done < num_files; i++) {
+ if (done[res[i].file])
+ continue;
+ this_op = &op[res[i].file][res[i].op_num];
/* Is what we have good enough for this op? */
if (satisfies(data, needs(this_op))) {
- /* Try this one next. */
- struct key_user tmp = res[0];
- res[0] = res[i];
- res[i] = tmp;
+ move_to_front(res, i);
if (sort_deps(filename, op, res+1, num-1,
- gives(this_op, data)))
+ gives(this_op, data), num_files))
return true;
+ restore_to_pos(res, i);
}
+ done[res[i].file] = true;
+ files_done++;
}
+
/* No combination worked. */
return false;
}
+static void check_dep_sorting(struct key_user user[], unsigned num_users,
+ unsigned num_files)
+{
+#if DEBUG_DEPS
+ unsigned int i;
+ unsigned minima[num_files];
+
+ memset(minima, 0, sizeof(minima));
+ for (i = 0; i < num_users; i++) {
+ assert(minima[user[i].file] < user[i].op_num);
+ minima[user[i].file] = user[i].op_num;
+ }
+#endif
+}
+
/* All these ops have the same serial number. Which comes first?
*
* This can happen both because read ops or failed write ops don't
* in which case we'll deadlock and report: fix manually in that case).
*/
static void figure_deps(char *filename[], struct op *op[],
- struct key_user user[], unsigned start, unsigned end)
+ struct key_user user[], unsigned num_users,
+ unsigned num_files)
{
- unsigned int i;
/* We assume database starts empty. */
const struct TDB_DATA *data = &tdb_null;
- /* What do we have to start with? */
- for (i = 0; i < start; i++)
- data = gives(&op[user[i].file][user[i].op_num], data);
-
- if (!sort_deps(filename, op, user + start, end - start, data))
- fail(filename[user[start].file], user[start].op_num+1,
+ if (!sort_deps(filename, op, user, num_users, data, num_files))
+ fail(filename[user[0].file], user[0].op_num+1,
"Could not resolve inter-dependencies");
+
+ check_dep_sorting(user, num_users, num_files);
}
-static void sort_ops(struct keyinfo hash[], char *filename[], struct op *op[])
+static void sort_ops(struct keyinfo hash[], char *filename[], struct op *op[],
+ unsigned int num)
{
unsigned int h;
int compare_serial(const void *_a, const void *_b)
{
const struct key_user *a = _a, *b = _b;
+
+ /* First, maintain order within any trace file. */
+ if (a->file == b->file)
+ return a->op_num - b->op_num;
+
+ /* Otherwise, arrange by serial order. */
return op[a->file][a->op_num].serial
- op[b->file][b->op_num].serial;
}
- /* Now sort into seqnum order. */
+ /* Now sort into serial order. */
for (h = 0; h < total_keys * 2; h++) {
- unsigned int i, same;
struct key_user *user = hash[h].user;
qsort(user, hash[h].num_users, sizeof(user[0]), compare_serial);
-
- /* Try to deal with same serial numbers. */
- for (i = 1, same = 0; i < hash[h].num_users; i++) {
- if (op[user[i].file][user[i].op_num].serial
- == op[user[i-1].file][user[i-1].op_num].serial) {
- same++;
- continue;
- }
-
- if (same) {
- figure_deps(filename, op, user, i-same-1, i);
- same = 0;
- }
- }
- if (same)
- figure_deps(filename, op, user, i-same-1, i);
+ figure_deps(filename, op, user, hash[h].num_users, num);
}
}
/* Create hash table for faster key lookup. */
hash = hash_ops(op, num_ops, num);
- /* Now handle the hard cases: same serial number. */
- sort_ops(hash, filename, op);
+ /* Sort them by serial number. */
+ sort_ops(hash, filename, op, num);
/* Create dependencies back to the last change, rather than
* creating false dependencies by naively making each one