+/* Test speed of memiszero */
+#include <ccan/time/time.h>
+#include <ccan/mem/mem.h>
+#include <stdlib.h>
+#include <stdio.h>
+#include <assert.h>
+
+#define MAX_TEST 65536
+
+int main(int argc, char *argv[])
+{
+ size_t n, i, max = argv[1] ? atol(argv[1]) : 100000000, runs;
+ char *arr;
+ size_t total = 0;
+
+ arr = calloc(1, max + MAX_TEST + 1);
+
+ runs = max;
+ /* First test even sizes case. */
+ for (n = 1; n <= MAX_TEST; n *= 2) {
+ struct timeabs start = time_now();
+ struct timerel each;
+
+ for (i = 0; i < runs; i++)
+ total += memeqzero(arr + i, n);
+ each = time_divide(time_between(time_now(), start), runs);
+ assert(each.ts.tv_sec == 0);
+ printf("%zu: %uns\n", n, (unsigned int)each.ts.tv_nsec);
+
+ /* Reduce runs over time, as bigger take longer. */
+ runs = runs * 2 / 3;
+ }
+
+ runs = max;
+ for (n = 1; n <= MAX_TEST; n *= 2) {
+ struct timeabs start = time_now();
+ struct timerel each;
+
+ for (i = 0; i < runs; i++)
+ total += memeqzero(arr + i, n+1);
+ each = time_divide(time_between(time_now(), start), runs);
+ assert(each.ts.tv_sec == 0);
+ printf("%zu: %uns\n", n+1, (unsigned int)each.ts.tv_nsec);
+ runs = runs * 2 / 3;
+ }
+
+ printf("total = %zu\n", total);
+ return 0;
+}